Answer:
4.5 miles
Step-by-step explanation:
Given
[tex]Middle\ School = (15,13)[/tex]
[tex]Library = (27,9)[/tex]
To solve this, we simply solve for the distance (D) between both points.
[tex]D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]
Where:
[tex](x_1,y_1) = (15,13)[/tex]
[tex](x_2,y_2) = (27,9)[/tex]
[tex]D = \sqrt{(27 - 25)^2 + (9 - 13)^2}[/tex]
[tex]D = \sqrt{(2)^2 + (-4)^2}[/tex]
[tex]D = \sqrt{4 + 16}[/tex]
[tex]D = \sqrt{20}[/tex]
[tex]D=4.472135955[/tex]
[tex]D=4.5[/tex] --- approximated
Since each unit is 1 mile. The distance is 4.5 miles
