Answer:
The new speed of the aircraft with respect to the ground is 1414.3 mph.
Explanation:
Given that,
Angle = 37°
Velocity of jet airliner = 693 mph
Velocity of wind = 798 mph
We know that,
The new velocity of the aircraft with respect to the ground
[tex]v=v_{a}+v_{w}[/tex]
We need to calculate the new speed of the aircraft with respect to the ground
Using formula for velocity
[tex]v=\sqrt{(v_{a})^2+(v_{w})^2+2v_{a}v_{w}\cos\theta}[/tex]
Put the value into the formula
[tex]v=\sqrt{(693)^2+(798)^2+2\times693\times798\cos37}[/tex]
[tex]v=1414.3\ mph[/tex]
Hence, The new speed of the aircraft with respect to the ground is 1414.3 mph.
