Answer:
The p-value is [tex]p-value = 0.0039854[/tex]
Step-by-step explanation:
From the question we are told that
The sample size is n = 1100
The population proportion is p = 0.50
The sample proportion is [tex]\^ p = 0.54[/tex]
The null hypothesis is [tex]H_o : p = 0.50[/tex]
The alternative hypothesis is [tex]H_a : p > 0.50[/tex]
Generally the test statistics is mathematically represented as
[tex]z = \frac{\^ p - p }{ \sqrt{\frac{ p(1 - p)}{n} } }[/tex]
=> [tex]z = \frac{ 0.54 - 0.54 }{ \sqrt{\frac{ 0.50 (1 - 0.50)}{1100} } }[/tex]
=> [tex]z = 2.6533[/tex]
Generally from the z-table the probability of 2.6533 for a right tailed test is
[tex]p-value = 0.0039854[/tex]
