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Enter the values of h and k so that y = x2 + 6x + 10 is in vertex form.

y = (x +
)2 +

Respuesta :

Answer:

y = (x + 3)^2 + 1

Step-by-step explanation:

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The equation in vertex form is [tex]y = (x + 3)^2 + 1[/tex], and the values of h & k are -3 and 1

What is the vertex form?

The vertex form of an equation is a quadratic equation, written in the form of a parabola

The equation is given as:

[tex]y = x^2 + 6x + 10[/tex]

Write out the constant

[tex]y = (x^2 + 6x) + 10[/tex]

Take the coefficient of x

[tex]k = 6[/tex]

Divide by 2

[tex]k/2 = 3[/tex]

Square the expression

[tex](k/2)^2 = 9[/tex]

So, we have:

[tex]y = (x^2 + 6x + 9 - 9) + 10[/tex]

Rewrite as:

[tex]y = (x^2 + 6x + 9) -9+ 10[/tex]

[tex]y = (x^2 + 6x + 9) + 1[/tex]

Express as a perfect square

[tex]y = (x + 3)^2 + 1[/tex]

Hence, the equation in vertex form is [tex]y = (x + 3)^2 + 1[/tex], and the values of h & k are -3 and 1

Read more about vertex forms at:

https://brainly.com/question/26738087