Respuesta :
Answer:
y = (x + 3)^2 + 1
Step-by-step explanation:
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The equation in vertex form is [tex]y = (x + 3)^2 + 1[/tex], and the values of h & k are -3 and 1
What is the vertex form?
The vertex form of an equation is a quadratic equation, written in the form of a parabola
The equation is given as:
[tex]y = x^2 + 6x + 10[/tex]
Write out the constant
[tex]y = (x^2 + 6x) + 10[/tex]
Take the coefficient of x
[tex]k = 6[/tex]
Divide by 2
[tex]k/2 = 3[/tex]
Square the expression
[tex](k/2)^2 = 9[/tex]
So, we have:
[tex]y = (x^2 + 6x + 9 - 9) + 10[/tex]
Rewrite as:
[tex]y = (x^2 + 6x + 9) -9+ 10[/tex]
[tex]y = (x^2 + 6x + 9) + 1[/tex]
Express as a perfect square
[tex]y = (x + 3)^2 + 1[/tex]
Hence, the equation in vertex form is [tex]y = (x + 3)^2 + 1[/tex], and the values of h & k are -3 and 1
Read more about vertex forms at:
https://brainly.com/question/26738087