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Part 2: Vertical Distance
1
do
2.942
d, = vertical distance
g = acceleration due to gravity (10m/s2)
t = time
How high was a brick dropped from if it falls in 2.5 seconds?
2.5 m
Ob
12.5 m
25 m
с
Od
31.25 m

Respuesta :

quasarJose

Answer:

31.25m

Explanation:

Given parameters:

   Acceleration due to gravity  = 10m/s²

    Time of drop = 2.5s

Unknown

Height of drop  = ?

Solution:

To solve this problem, we must note that the brick was originally at rest. The appropriate motion equation to solve this is shown below;

          H  = ut + [tex]\frac{1}{2}[/tex]gt²

H is the height

u is the initial velocity

g is the acceleration due to gravity

t is the time taken

          Input the parameters and solve;

      H = 0 +  [tex]\frac{1}{2}[/tex] x 10 x 2.5²

     H = 31.25m

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