[tex]v + 8 < 3[/tex]
Subtract sides -8
[tex]v + 8 - 8 < 3 - 8[/tex]
[tex]v < - 5[/tex]
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[tex]8v < - 40[/tex]
Divided sides by 8
[tex] \frac{8}{8}v < \frac{ - 40}{8} \\ [/tex]
[tex]v < - 5[/tex]
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Done.... ♥️♥️♥️♥️♥️
Answer:
v<-5 or v>5
Step-by-step explanation:
first i have the same questions on a bigideasmath assignment and this is wasier anyway You have v+8<3, first you subtract 8 as its the opposite of addition and it would become -5 making it v<-5 next theres the other side starting off with 8v<-40, you would start off with divided 40 by 8 equaling -5 making the equation v<-5. I know this is late but your welcome
