What are the missing parts that correctly complete the proof?

Given: point P is on the bisector of ABC.

Prove: point P is equidistant from the sides of ABC.

1. BP is the bisector of ABC- given

2. ABP≈CBP- ?

3. BXP and BYP are right angles- given

4. ?- all right angles are congruent

5. BP≈BP- ?

6. BXP≈BYP- ?

7. ?- corresponding parts of congruent triangles are congruent

8. Point P is equidistant from the sides of ABC- definition of equidistant

What are the missing parts that correctly complete the proof Given point P is on the bisector of ABC Prove point P is equidistant from the sides of ABC 1 BP is class=

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Answer:

Hello, I just took the test today. I will attach a screenshot. I hope I am not too late answering your question.

This question stumped me too at first. I hope this helps!

Ver imagen sammymurphy259

The missing parts that correctly complete the proof are;

2) Definition of a bisector

4) ∠BXP ≅ ∠BYP.

5) Reflexive property of congruence.

6) AAS congruence theorem.

7) Corresponding sides of congruent triangles are congruent.

We are given;

Point P is on the bisector of ∠ABC.

  • 2) ∠ABP ≅ ∠CBP; The symbol ≅ means congruent. This means they are equal and it is true because it corresponds with the definition of a bisector means dividing into 2 equal parts.

  • 4) All right angles are congruent; Congruent means equal and the two right angles we have in the image are; ∠BXP and ∠BYP. Thus, we can write; ∠BXP ≅ ∠BYP.

  • 5) BP ≅ BP; This means that Line BP is congruent and equal to itself and this fulfils the theorem called reflexive property of congruence.

  • 6) ΔBXP ≅ ΔBYP; This means ΔBXP is congruent to ΔBYP. Since we have established that ∠BXP ≅ ∠BYP; ∠ABP ≅ ∠CBP; BP ≅ BP. It means we have 2 corresponding angles and one corresponding side equal to each other from the 2 congruent triangles and so we can say this fulfils the AAS congruence theorem.

  • 7) PX ≅ PY; This means PX is congruent to PY. From congruence theorem, corresponding sides of congruent triangles are congruent.

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