find the measures of angles 1, 2, and 3

x = 33°
Then :-
m∠1 = 33° ( angle x and angle 1 are corresponding angles on a transversal )
m∠1 + m∠2 = 90° ( angle 1 and angle 2 are complementary angles )
33 + ∠2 = 90
∠2 = 90 - 33
m∠2 = 57°
m∠1 + m∠3 = 180° ( angle 1 and angle 3 are a linear pair )
33 + ∠3 = 180°
∠3 = 180 - 32
m∠3 = 147°