Answer:
The side length of each square is 2.12 units.
The length ad width of the rectangle are 2.12 and 4.24 units
Step-by-step explanation:
Let the width of the rectangle is x,
So, the length of the rectangle is 2x.
Area of the rectangle = 9 sq. units
[tex]9 = 2x \times x[/tex] [as area = length x width]
[tex]\Rightarrow 9 = 2x^2[/tex]
[tex]\Rightarrow x^2 = \frac{9}{2}=4.5[/tex]
[tex]\Rightarrow x = 1.5\sqrt{2}=2.12[/tex] units
So, width of the rectangle, x= 2.12 units and
the llengthof the rectangle, 2x= 2 x 2.12= 4.24 units.
After division of the rectangle into two equal square, so, the area of each square will be half of the area of the rectangle.
The area of the rectangle = 9/2=4.5 square units.
Let a be the length of the sides of the square, so
Area [tex]= a^2[/tex]
[tex]\Rightarrow a^2=4.5[/tex]
[tex]\Rightarrow[/tex] [tex]a = 1.5\sqrt{2}=2.121[/tex]
Hence, the side length of each square = 2.12 units.
