Point P partitions directed segment AB in the ratio of 3:4.

What is the total number of congruent sections/parts? (what

is the k value?)

how many congruent sections are there

Respuesta :

Answer:

Total number of congruent sections/parts = 7

[tex] k = \frac{3}{7} [/tex]

Step-by-step explanation:

Given that partitions directed segment AB such that AP : PB = 3 : 4, this implies that:

There are 7 parts/congruent sections that AB has been divided into.

Also, point P, partitions AB in the ratio 3:4.

Therefore, there are a total of 7 congruent sections/parts.

Value of k:

Value of k = numerator of the original ratio ÷ sum of numerator and denominator of the original ratio

[tex] k = \frac{3}{3 + 4} [/tex]

[tex] k = \frac{3}{7} [/tex]