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EDGE 2020 The average monthly high temperatures for Phoenix, Arizona from the years 1981-2010 are shown in the table below, with the value 1 representing the month of January, and the value of 12 representing the month of December. Complete the following steps to model the curve using the sine function.

a. Make a scatterplot of the data.

b. What is the minimum temperature in the data set?

c. What is the maximum temperature in the data set?

d. What is the vertical shift, k, for the data set?

e. What is the amplitude, a, for the data set?

f. What is the period and frequency factor for the data set?

g. What is the phase shift for the data set?

h. Write an equation using the sine function that models this data set.

i. When would you expect the temperature in Phoenix to be 82°?

EDGE 2020 The average monthly high temperatures for Phoenix Arizona from the years 19812010 are shown in the table below with the value 1 representing the month class=

Respuesta :

Answer:

a. Please find attached the required scatter plot

b. The minimum temperature in the data set is 67°F

c. The maximum temperature in the data set is 106°F

d. The vertical shift for the data set is 67°F

e. The amplitude 19.5 °F

f. The period is 12 months, the frequency = 1/12 months

h. The sine function equation that models the data set is 19.5·sin(π·t/6 - π/2) + 86.5

i. After the second and before the third month or after the ninth and before the 10th month

Step-by-step explanation:

The equation for the sinusoidal variation of temperature with time can be presented as follows;

y = A·sin(Bt + C) + D

Where;

A = The amplitude = (The Maximum value - The minimum value)/2

The amplitude = (106 - 67)/2 = 19.5°F

B = 2·π/(The period) = 2·π/12 = π/6

t = The time in months

C = The phase shift = -π/2

D = The midline = (The Maximum value + The minimum value)/2 = (106 + 67)/2 = 86.5 °F

The equation that models the data = 19.5·sin(π·t/6 - π/2) + 86.5

When the temperature is 82°, we have;

82 = 19.5·sin(π·t/6 - π/2) + 86.5

82 - 86.5 = 19.5·sin(π·t/6 - π/2)

-4.5°F = 19.5·sin(π·t/6 - π/2)

sin⁻¹(-4.5/12) = π·t/6 - π/2

-0.3844  = π·t/6 - π/2  

-0.2329 = π·t/6 - π/2  

t = 2.55 or 12 - 2.55 = 9.44

Which is either after the second and before the third month or after the ninth and before the 10th month.

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lhmarianateixeira

In this exercise we have to use the function knowledge to calculate the temperature that is requested in each alternative, so we have to:

a. The answer is in the scatter plot  

b. The minimum is 67°F

c. The maximum is 106°F

d. The vertical shift is 67°F

e. The amplitude 19.5 °F

f. The frequency is 1/12 months and the period is 12.

h. The sine function equation that models the data set is [tex]19.5sin(\pi t/6 - \pi /2) + 86.5[/tex]

i. After the second and before the third month or after the ninth and before the 10th month

The equation for the sinusoidal variation of temperature with time can be presented as follows;

[tex]y = Asin(Bt + C) + D[/tex]

Where;

  • A =  [tex](106 - 67)/2 = 19.5\°F[/tex]
  • B = [tex]2\pi /(T) = 2\pi/12 = \pi/6[/tex]
  • t = 12
  • C =  [tex]\pi/2[/tex]
  • D =  [tex](106 + 67)/2 = 86.5 \°F[/tex]

The equation that models the data is given by:

[tex]19.5sin(\pi t/6 - \pi/2) + 86.5[/tex]

When the temperature is 82°, we have;

[tex]82 = 19.5sin(\pi t/6 - \pi/2) + 86.5\\82 - 86.5 = 19.5sin(\pi t/6 - \pi/2)\\-4.5\°F = 19.5sin(\pi t/6 - \pi/2)\\sin^{-1}(-4.5/12) = \pi t/6 - \pi /2\\-0.3844 = \pi t/6 - \pi /2 \\-0.2329 = \pi t/6 - \pi /2\\t = 2.55 \ or \ 9.44[/tex]

Which is either after the second and before the third month or after the ninth and before the 10th month.

See more about temperature at brainly.com/question/15267055

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