A device for acclimating military pilots to the high accelerations they must experience consists of a horizontal beam that rotates horizontally about one end while the pilot is seated at the other end. In order to achieve a radial acceleration of 29.9 m/s2 with a beam of length 5.33 m , what rotation frequency is required

Respuesta :

Answer:

Rotation frequency is 0.377 hertz.

Explanation:

After a careful reading of statement, we need to apply the concept of radial acceleration due to uniform circular motion, whose formula is:

[tex]a_{r} = \omega^{2}\cdot L[/tex] (Eq. 1)

Where:

[tex]a_{r}[/tex] - Radial acceleration, measured in meters per square second.

[tex]\omega[/tex] - Angular velocity, measured in radians per second.

[tex]L[/tex] - Length of the beam, measured in meters.

Now we clear the angular velocity within:

[tex]\omega = \sqrt{\frac{a_{r}}{L} }[/tex]

If [tex]a_{r} = 29.9\,\frac{m}{s^{2}}[/tex] and [tex]L = 5.33\,m[/tex], the angular velocity is:

[tex]\omega = \sqrt{\frac{29.9\,\frac{m}{s^{2}} }{5.33\,m} }[/tex]

[tex]\omega \approx 2.368\,\frac{rad}{s}[/tex]

The frequency is the number of revolutions done by device per second and can be found by using this expression:

[tex]f = \frac{\omega}{2\pi}[/tex] (Eq. 2)

Where [tex]f[/tex] is the frequency, measured in hertz.

If we know that [tex]\omega \approx 2.368\,\frac{rad}{s}[/tex], then rotation frequency is:

[tex]f = \frac{2.368\,\frac{rad}{s} }{2\pi}[/tex]

[tex]f = 0.377\,hz[/tex]

Rotation frequency is 0.377 hertz.