Answer:
The magnitude of the resistive force exerted by the water is [tex]6.85\times 10^{5}[/tex] newtons.
Explanation:
By First and Second Newton's Law, the resistive force exerted by the water on the cruise ship has the same magnitude of forward thrust, with which it is antiparallel to. The equation of equilibrium for the luxury liner is:
[tex]\Sigma F = F-R = 0[/tex] (Eq. 1)
Where:
[tex]F[/tex] - Forward trust, measured in newtons.
[tex]R[/tex] - Resistive force exerted by the water, measured in newtons.
From (Eq. 1), we get that: ([tex]F = 6.85\times 10^{5}\,N[/tex])
[tex]R = F[/tex]
[tex]R = 6.85\times 10^{5}\,N[/tex]
The magnitude of the resistive force exerted by the water is [tex]6.85\times 10^{5}[/tex] newtons.
