Answer:
49.925N
Explanation:
According to newton's second law of motion:
[tex]\sum Fx = ma_x[/tex]
[tex]\sum Fx[/tex] is the sum of force along the x component
m is the mass of the crate
ax is the acceleration
[tex]Fm - Fk = ma_x[/tex]
Fk is the magnitude of the force of kinetic friction
Given
Fm = 93.7
m = 42.5kg
a = 1.03m/s²
Substitute into the formula:
[tex]93.7 - Fk = (42.5)(1.03)\\93.7-Fk = 43.775\\Fk = 93.7 - 43.775\\Fk = 49.925N[/tex]
Hence the magnitude of the force of kinetic friction (in N) acting on the crate is 49.925N
