Answer:
424.773N
Explanation:
Taking the sum of force along the incline. The forces acting along the incline is the moving force P and the frictional force Ff
P = mgsintheta
Ff = nR = nmgcostheta
n is the coefficient of friction
R is the normal reaction
m is the mass of the block
g is the acceleration due to gravity
[tex]\sum Fx = 0\\P-Ff = 0\\mgsin\theta - \mu mgcos\theta = 0\\mgsin\theta = \mu mgcos\theta\\P = \mu mgcos\theta\\P = (0.2)250(9.81)cos30^0\\P = 490.5cos30^0\\P = 490.5(0.8660)\\P = 424.773N\\[/tex]
Hence the force P required to start moving the block up the incline is 424.773N
