Respuesta :
Answer:
Kinetic energy = 1500 J
Explanation:
The computation of the block's kinetic energy is shown below:
As we know that
Conservation of energy is
PE_i + KE_i = PE_f + KE_f
where,
Initial Potential energy = PE_i = m gh = 10kg× 10m/s^2 × 10m = 1000 J
Initial Kinetic energy = KE_i = (0.5) m V^2 = (0.5) (10 kg) (10 m/s)^2 = 500 J
Final potential energy = PE_f = mgh = 0 Â Â Â
As h = 0 which is at reference line
So
PE_i + KE_i = PE_f + KE_f
Now put these valeus to the above formulas
1000 J + 500 J = 0 + KE_f
After solving this
Kinetic energy = 1500 J
The block's kinetic energy is closest to 1500 Joules.
Kinetic energy :
The energy is always conserved.
So that, the total kinetic energy will be sum of initial potential energy and kinetic energy during falling.
Given that, mass(m)=10kg, v=10m/s, h=10m,g=10m/s^2
       K.E=(1/2)mv^2 + mgh
       K.E=(1/2)*10*100 + (10*10*10)
       K.E=500 + 1000=1500Joule
The  block's kinetic energy is closest to 1500 Joules.
Learn more about the kinetic energy here:
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