. Let the random variable P be the air pressure in a car tire, and assume that P is uniformly distributed between 29 and 34 pounds per square inch (psi). Recall that this means that the density curve for P is a flat, horizontal line at some constant level c above the interval from 29 psi to 34 psi. (a) Find the probability that the pressure of a tire will be above 31.7 psi.

Respuesta :

Answer:

The probability is [tex]P(X >  31.7) = 0.54[/tex]

Step-by-step explanation:

From the question we are told that

   P  is uniformly distributed between[tex]a=  29[/tex] and [tex]b=34[/tex] pounds per square inch (psi)

Generally the uniform distribution cumulative distribution  function is mathematically represented as

        [tex]F(x ) =  \left \{ {{ 0  \\ \ \ \ \ \  x \le a} \atop { \frac{x-a}{b-a} \ \ \ \ \ \ \ \ a <  x < b}}  \atop {1 \ \ \ \ \ \ \ \ \ \ \ \ \ x \ge  b}} \right.[/tex]

Generally the probability that the pressure of a tire will be above 31.7 psi

     [tex]P(X >  31.7) =  \frac{ 31 . 7  -  a }{b-a}[/tex]

=>  [tex]P(X >  31.7) =  \frac{ 31 . 7  -  29 }{34-29}[/tex]

=>  [tex]P(X >  31.7) = 0.54[/tex]