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A ball is thrown straight up with a velocity of 16 m/s; what will be its velocity 2.0s after being released?
NOTE THE ANSWER IS -3.6M/S
CAN YOU JUST HELP TELL ME WHAT TO DO TO GET TO THAT ANSWER

Respuesta :

Answer:

Final velocity v = -3.6 m/s

Explanation:

Given:

Initial velocity u = 16 m/s

Total time = 2 s

Find:

Final velocity v

Computation:

Acceleration = -9.8 m/s²

v = u + at

v = 16 + (-9.8)(2)

v = -3.6 m/s

Final velocity v = -3.6 m/s

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