Answer:
θ = 6.832 / a 10⁻⁷ rad
a= 1 mm, θ = 6.832 10⁻⁴ rad
Explanation:
The limit of the resolution of a system is given by the first zero of the diffraction pattern for a slit is
a sin θ = m λ
m = 1
a sin θ = λ
sin θ = λ / a
in the case of circular tightness it must be solved in polar coordinates giving
sin θ = 1.22 λ / a
as in diffraction experiments the angles are very small we can approximate the sine to the angle, in radians
θ = 1.22 λ / a
Let's calculate
θ = 1.22 560 10⁻⁹ / a
θ = 6.832 / a 10⁻⁷ rad
In order to finish the calculation, the diameter of the objective lens is needed, for a sample let's use a diameter 1 mm = 10⁻³ m
θ = 6.832 10⁻⁴ rad
