Answer:
[tex]1.90\times10^{3}kg.m^2[/tex]
Explanation:
The computation of the moment of inertia of the three rotor blades is shown below:
Given that
Three rotor helicopter blades = 3.75 mm long
Mass = 135 kg
Based on the above information
As we know that
Axis at the end is
[tex]I_1 = \frac{1}{3} ML^2[/tex]
Now the total moment of inertia is
[tex]I = 3I_i\\\\= ML^2\\\\= (135 kg) (3.75m)^2\\\\= 1.90\times10^{3}kg.m^2[/tex]
Hence, the moment of inertia of the three rotor blades is [tex]1.90\times10^{3}kg.m^2[/tex]
We simply applied the above formula and the same is to be considered
