Answer:
The fluid speed along the origin is [tex]|v| = 5\ ft /s[/tex]
The fluid speed of along x-axis(y = z = 0) is [tex]|v| = \sqrt{ 9 + (x +4)^2} \ ft/s[/tex]
Explanation:
From the question we are told that
The velocity is [tex]v = (5z -3)i + (x + 4 )j + 4yk[/tex]
Generally at origin [tex]x = 0 \ m , \ y = 0\ m \ , z = 0 \ m[/tex]
So at the origin the equation becomes
[tex]v = -3i + 4j +0k[/tex]
Generally the magnitude of the speed at origin is mathematically represented as
[tex] |v| = \sqrt{ (-3)^2 + (4)^2 + (0)^2} [/tex]
=> [tex]|v| = 5\ ft /s[/tex]
Generally the velocity on the x- axis ( y= z = 0 ) is mathematically represented as
[tex]v = -3i + (x + 4)j[/tex]
Generally the magnitude of the speed is
[tex]|v| = \sqrt{ (-3)^2 + (x +4)^2}[/tex]
[tex]|v| = \sqrt{ 9 + (x +4)^2} \ ft/s[/tex]
