ggraves1
contestada

Which of the following equations have no solution? Check all that apply.
6x + 1 = 3(2x – 4)
2 – 5x = 7x – 12
4(3 – x) = 2(6 – 2x)
5(x + 2) = 2(x – 4)
–4(x + 3) = 4(–x – 1)

Respuesta :

ywhaty0

Answer:

–4(x + 3) = 4(–x – 1) and 6x + 1 = 3(2x – 4)

Step-by-step explanation:

grantgreving1

Answer:

1 ans 5

Step-by-step explanation:

no solution              –––

6x + 1 = 3(2x - 4)

6x + 1 = 6x - 4

6x - 6x + 1 = 6x - 6x - 4

1 ≠ -4

one solution

2 - 5x = 7x - 12

2 -5x + 5x = 7x + 5x - 12

2 = 12x - 12

2 + 12 = 12x - 12 + 12

14 = 12x

x = 14/12

infinite solutions

4(3 - x) = 2(6 - 2x)

12 - 4x = 12 - 4x

12 - 12 - 4x + 4x = 12 - 12 - 4x + 4x

0 + 0 = 0 + 0

0 = 0

one solution

5(x + 2) = 2(x - 4)

5x + 10 = 2x - 8

5x - 5x + 10 + 8 = 2x - 5x - 8 + 8

18 = -3x

x = -6

no solution                            –––

-4(x + 3) = 4(-x - 1)

-4x + 4x - 12 = -4x + 4x - 4

-12 ≠ -4