A falling skydiver is accelerating in the downward direction at 3.29 m/s^2. The mass of the skydiver (including parachute gear) is 67.2 kg. Determine the air resistance force on the skydiver (and accompanying parachute).

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Answer:

The force due to air resistance on the skydiver is 438.1 N.

Explanation:

You need to balance forces. If we use the following notation:

Net force on skydiver = F

Force on skydiver due to gravity = F(grav)

Force on skydiver due to friction or air resistance = F(air)

Then:

F = F(grav) - F(air)

because the force of air resistance acts against the force from gravity. You can rearrange this to get:

F(air) = F(grav) - F

Then you can use the equation F = ma to get:

F(air) = ma(grav) - ma

where:

m = mass of skydiver (given in question) = 67.2kg

a(grav) = acceleration of an object due to gravity = g = 9.81 m/s/s on Earth

a = actual acceleration (given to you in question) = 3.29 m/s/s

Simplify the equation to get:

F(air) = m * [g - a]

F(air) = 67.2 * [9.81 - 3.29]

F(air) = 67.2 * [6.52]

F(air) = 438.1 N

Answer:

This is the complete answer and solution for the problem

Given:

a = 3.29 m/s²

m = 67.2 kg

Unknown:

Force = ?

Formula and Solution:

F = ma

F = (67.2 kg)(3.29 m/s²)

Final answer:

221.09 kg.m/s² or simplify as 221.09 N