How to get 51 by useing four numbers 8 5 6 7

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facundo3141592 facundo3141592 · Answer 1 · 2020-10-29T01:07:50+01:00

Answer:

We want to get to 51 using only the numbers 5, 6, 7 and 8.

First, let's write remember that:

8 = 2^3

6 = 3*2

Then we can start with:

8*6 = 48

This is close to the number we want, we are 3 units below.

And 8 - 7 = 1

7 - 5 = 2

Then we can do:

8*6 + (8 - 7) + (7 - 5) = 51.

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aksnkj aksnkj · Answer 2 · 2021-12-21T14:21:12+01:00

One of the possible combinations of 8, 5, 6, and 7 to get 51 should be [tex]5\times7+8+6+7-5[/tex].

It is required to get 51 by using four numbers 8, 5, 6, and 7.

There can be multiple combinations of such results.

Let try one by using simple algebra.

First, the multiplication numbers 5 and 7 will give us 35 which is close enough to the number which we want.

Now, add 8 and 6 to the above result. We will get,

[tex]5\times7+8+6=35+8+6=49[/tex]

To get the final result of 51, we need 2 to be added to the above result.

So, add [tex]7-5=2[/tex] to the above conclusion.

[tex]5\times7+8+6+(7-5)=35+8+6+(7-5)=49+2\\=51[/tex]

Therefore, one of the combinations of 8, 5, 6, and 7 to get 51 should be [tex]5\times7+8+6+7-5[/tex].

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https://brainly.com/question/226685