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Answer:
- quadrants: III, IV
- vertex: (0, 0)
- x-intercepts: (0, 0) -- at the vertex
- dashed line, shaded inside, opens down
Step-by-step explanation:
Compared to vertex form ...
y = a(x -h)^2 +k
we find that a=-3, (h, k) = (0, 0). That is, the vertex is (0, 0).
A parabola whose vertex is on the x-axis has that as its only x-intercept. (The x-intercept (vertex) is NOT in the solution set.)
The negative leading coefficient tells you the graph opens downward. The y < ( ) comparison tells you shading is below the boundary line, which is dashed. Below a downward-opening parabola is inside the parabola.
The two offered points are on the x-axis, so not in the solution set.
