Answer:
5. 0.8334 g
Explanation:
Given data:
Volume of water vapors = 3 L
Temperature = 125°C
Pressure = 383 torr
Mass of water vapors = ?
Solution:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
125+273 = 398 K
383torr × 1 atm /760 torr = 0.503947 atm
PV = nRT
0.503947 atm × 3L = n × 0.0821 atm.L/ mol.K × 398 K
1.5111841 atm.L = n ×32.68 atm.L/ mol
n = 1.512 atm.L /32.6758 atm.L/ mol
n = 0.0463 mol
Mass of water vapors:
Mass = number of moles × molar mass
Mass = 0.0463 × 18 g/mol
Mass = 0.8334 g
