At a dam, the water surface has a height of 120 m above a turbine. The turbine uses 85% of the water's potential energy. If 1800 kg of water flows through the turbine per minute, how much power will come from the turbine?

Respuesta :

Answer:

Et = 30018 [W]

Explanation:

To solve this problem we must use the definition of potential energy, which is expressed by the following equation:

[tex]E_{p} =m*g*h[/tex]

where:

Ep = potencial energy [W]

g = gravity acceleration [m/s^2]

h = elevation = 120 [m]

m = mass flow = [1800/min]

But in order to get watts into potential energy, we must convert the mass flow from kilograms per minute to kilograms per second.

[tex]1800[\frac{kg}{min} ]*\frac{1}{60}\frac{min}{s}=30[\frac{kg}{s} ][/tex]

Ep = 30*9.81*120

Ep = 35316 [W]

If we use  85% of the potential  energy will have:

Et = 35316*0.85

Et = 30018 [W]