Answer:
T₂ = 298 K
Explanation:
Given data:
Initial volume = 500 mL
Initial pressure = 38.0 KPa
Initial temperature = 298 K
Final temperature= ?
Final pressure = 76.0 KPa
Final volume = 250 mL
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = = P₂V₂T₁ / P₁V₁
T₂ = 76.0 KPa × 250mL × 298 K / 38.0 KPa × 500 mL
T₂ = 5662000 KPa.mL. K /19000 KPa. mL
T₂ = 298 K
