Answer:
56.9kg
Explanation:
Given parameters:
∆Hfusion = 334J/g
Amount of energy = 19kJ or 19 x 10³J
Initial temperature = 0°C
Unknown:
Quantity of ice melted = ?
Solution:
This process is a simple phase change from ice to water at the same temperature.
H = mL
m is the mass of the ice
L is the heat of fusion
H is the amount of supplied heat
Insert the parameters and solve;
19 x 10³ = m x 334
m = [tex]\frac{19000}{334}[/tex] = 56.9kg
