Answer: The balanced reaction equation is:
4
F
e
(
s
)
+
3
O
2
(
g
)
→
2
F
e
2
O
3
(
s
)
Initial moles of oxygen reactant (given) =
12.0
m
o
l
According to the balanced equation the iron and oxygen reactants combine in a 4:3 molar ratio. Therefore for complete consumption of both reactants we require:
Initial moles of iron reactant =
4
3
×
12.0
m
o
l
=
16.0
m
o
l
The number of mole of Fe needed to react with 12 moles of O₂ is 16 moles
We'll begin by writing the balanced equation for the reaction. This is given below:
3O₂ + 4Fe —> 2Fe₂O₃
From the balanced equation above,
3 moles of O₂ reacted with 4 moles of Fe.
With the above information, we can obtain the number of mole of Fe required to react with 12 moles of O₂. This can be obtained as follow:
From the balanced equation above,
3 moles of O₂ reacted with 4 moles of Fe.
Therefore,
12 moles of O₂ will react with = [tex]\frac{12 * 4 }{3}\\\\[/tex] = 16 moles of Fe
Thus, 16 moles of Fe are needed to react with 12 moles of O₂
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