A 5.0g sample of O₂ is in a container at STP, then the volume of the container is 3.49 L.
Volume of oxygen sample at STP will be calculated by using the ideal gas equation as:
PV = nRT, where
P = pressure = 1 atm
V = volume of gas = ?
R = universal gas constant = 0.082 L.atm/K.mol
T = temperature = 273K
n is the moles of oxygen sample and it will be calculated as:
n = W/M, where
W = given mass = 5g
M = molar mass of O₂ = 32g/mol
n = 5/32 = 0.156 moles
On putting all values on above equation, we get
V = (0.156)(0.082)(273) / (1)
V = 3.49 L
Hence required volume of gas sample is 3.49 L.
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