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A rocket is launched from the ground with an initial velocity of 25 miles per hour. When the rocket reaches its highest point, it has a velocity of zero for a split second. What is the highest of the rocket in meters when it reaches its highest point?

Respuesta :

Answer:

s = 51305.88 m

Explanation:

Initial velocity of a rocket, u = 25 mph

We need to find the maximum height of the rocket when it reaches its highest point. At this point, the final velocity of the rocket is equal to 0, v = 0

Using the equation of motion,

[tex]v^2-u^2=2as[/tex]

Here, a = -g and s is the height reached by rocket

[tex]-u^2=-2gs\\\\s=\dfrac{u^2}{2g}\\\\s=\dfrac{(25)^2}{2\times 9.8}\\\\s=31.88\ \text{miles}[/tex]

We know that, 1 mile = 1609.34 metre

31.88 miles = 51305.88 m

So, the height reached by the rocket is 51305.88 m.