Answer:
Equatorial sites
Explanation:
The choice of the location of bond pairs or lone pairs depends on the difference between the Xax-E-Xeq and Xeq-E-Xeq bond angles. Where X is a bonding group and E is a lone pair.
It follows that if we place the lone pair in an equatorial site, the structure is less crowded and there is less repulsion than when we place the lone pairs in an axial site.
Summarily, a lone pair occupies more space around the centeral atom than a bond pair hence it needs to be placed at an equatorial site where it experiences less repulsion than when it is placed in an axial site.
