Answer:
F = 91.08 N
Explanation:
It is given that,
Mass of a chair, m = 23 kg
Acceleration of the chair, a = 0.53 m/s²
The coefficient of kinetic friction between the chair and the floor is 0.35
We need to find the magnitude of the applied force. Let f is the frictional force and F is the applied force. We can use the equation of motion as follows :
F-f=ma
Also, [tex]f=\mu mg[/tex]
So,
[tex]F-\mu mg=ma\\\\F=m(a+\mu g)\\\\\text{Putting all the values to find F}\\\\F=23\times (0.53+0.35\times 9.8)\\\\F=91.08\ N[/tex]
So, the magnitude of the applied force is 91.08 N.
