Answer with Step-by-step explanation:
I would like to answer Part 4 first.
Part 4: What linear equation in standard form can she use to model the​ situation?
The situation says:
A total of $30 can be spent on "x" number of pounds of Cheddar Cheese and "y" number of pounds of Swiss Cheese.
Mathematically:
$30 = A*x + B*y
Here "A" is the price of Cheddar cheese and "B" is the price of Swiss cheese.
Part 1: How many pounds of cheese can Keisha get if she buys only Cheddar​ cheese?
Answer:
If she is going to buy only Cheddar cheese it means she will not buy Swiss which means "Y=0". This implies that:
$30 = A*x + B*0
$30 = A*x
x = $30 / A
I don't know the price of Cheddar Cheese, we can suppose it is $6 per pound.
So by putting values, we have:
x = $30 / $6 = 5 pounds
Part 2: Only Swiss​ cheese?
Answer:
Just like part 1, here "X=0". This implies that:
$30 = A*0 + B*y
$30 = B*y
x = $30 / B
I don't know the price of Swiss Cheese, we can suppose it is $10 per pound.
So by putting values, we have:
x = $30 / $10 = 3 pounds
Part 3: A mixture of both​ cheeses?
Answer:
There is number of answers to this question because the purchase of the type of cheese depends upon Keisha's priorities and desires.
