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A magnetic field of magnitude 0.360 T is oriented perpendicular to the plane of a circular loop. HINT (a) Calculate the loop radius (in m) if the magnetic flux through the loop is 2.65 Wb. m (b) Calculate the new magnetic flux (in Wb) if the loop radius is doubled.

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onyebuchinnaji

Answer:

(a)  the loop radius (in m) = 1.531 m

(b) the new magnetic flux, when the loop radius is doubled = 10.61 Wb

Explanation:

Given;

magnitude of magnetic field, B = 0.36 T

magnetic flux, Ф = 2.65 Wb

(a)  the loop radius (in m)

magnetic flux is given by;

Ф = BA

Where;

A is the circular area of the loop

A = πr²

Ф = B.πr²

[tex]r = \sqrt{\frac{\phi}{B\pi} }\\\\ r = \sqrt{\frac{2.65}{0.36\pi} }\\\\r = 1.531 \ m[/tex]

(b) the new magnetic flux, when the loop radius is doubled

Ф = B.πr²

Ф = 0.36 x π x (2 x 1.531)²

Ф = 10.61 Wb

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