Answer:
The height above the top of the window the stone fell is 2.57 m
Explanation:
Given;
time of stone fall, t = 0.31 s
distance the stone travel, y = 2.2m
The velocity of the stone when it travel past the window is given by;
v = y/t
v = 2.2 m / 0.31 s
v = 7.097 m/s
The height of fall with this final velocity is given by;
v² = u² + 2gh
where;
u is the initial velocity of the stone = 0
h is the height of fall
v² = 2gh
h = v² / 2g
h = (7.097² ) / (2 x 9.8)
h = 2.57 m
Therefore, the height above the top of the window the stone fell is 2.57 m
