The sum of the measures of the angles of all triangles is 180°. If one angle of the triangle measures 45°, and the other two angles are equal, what is the measure of each of the other two angles? Please hurry, This question is on a timed test and I have 30 minutes left.

Respuesta :

Answer:

[tex]\alpha = 67.5[/tex]

Step-by-step explanation:

Represent the first angle with [tex]\theta[/tex]

[tex]\theta = 45[/tex]

Represent the equal angles with [tex]\alpha[/tex]

So:

[tex]\alpha + \alpha + \theta = 180[/tex]

Substitute 45 for [tex]\theta[/tex]

[tex]\alpha + \alpha + 45 = 180[/tex]

Subtract 45 from both sides

[tex]\alpha + \alpha + 45 - 45= 180 - 45[/tex]

[tex]\alpha + \alpha = 135[/tex]

[tex]2\alpha = 135[/tex]

Divide both sides by 2

[tex]\alpha = 135/2[/tex]

[tex]\alpha = 67.5[/tex]

Hence:

The measure of the other angles is 67.5