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If the peak wavelength of a star at rest is 830 nm, but astronomers on earth observer that is has been shifted by 3.2 nm. Then how fast is the star moving relative to the earth

Respuesta :

Answer:

The speed is  [tex]v  =   1.16 *10^{6} \  m/s [/tex]  

Explanation:

From the question we are told that

   The  peak wavelength is  [tex]\lambda  = 830 \  nm  =  830  *10^{-9} \ m[/tex]

   The magnitude of the shift is  [tex]\Delta  \lambda = 3.2 nm  =  3.2*10^{-9} \  m[/tex]

Generally the doppler shift equation is mathematically represented as

      [tex]\frac{\Delta \lambda}{ \lambda}  =  \frac{v}{c}[/tex]

=>   [tex]v  =  c * [\frac{\Delta  \lambda}{\lambda} ][/tex]

Here c is the speed of light with value  [tex]=  3.0*10^{8} \  m/ s[/tex]

So

    [tex]v  =  3.0*10^{8}  * [\frac{  3.2*10^{-9}{830  *10^{-9}} ][/tex]

=>  [tex]v  =   1.16 *10^{6} \  m/s [/tex]