Answer:
The lateral magnification of the object is [tex]m = 2 [/tex]
Explanation:
From the question we are told that
The object distance is [tex]u = 10 \ cm[/tex]
The focal length is [tex]f = 20 \ cm[/tex]
Generally from the lens formula
[tex]\frac{1}{f} = \frac{1}{u} + \frac{1}{v}[/tex]
Here v is the image distance
So
[tex]\frac{1}{20} = \frac{1}{10} + \frac{1}{v}[/tex]
=> [tex]\frac{1}{20} - \frac{1}{10} = \frac{1}{v}[/tex]
=> [tex] - \frac{1}{20} = \frac{1}{v}[/tex]
=> [tex] v = -20\ cm[/tex]
Generally the lateral magnification is mathematically represented as
[tex]m = - \frac{v}{u}[/tex]
[tex]m = - \frac{-20 }{10}[/tex]
[tex]m = 2 [/tex]
