Answer:
A = 41.67 m²
Explanation:
- The intensity is defined as power received per unit surface, as follows:
[tex]I = \frac{P}{A} = 1 kW/m2 (1)[/tex]
- By definition, power is just the rate of change of energy with time, so we can write the following equation:
[tex]P = \frac{\Delta E}{\Delta t} (2)[/tex]
- From the givens, we know the following:
- ΔE = 150 MJ
- Δt = 1 hour = 3600 sec.
⇒ [tex]P = \frac{150 MJ}{3600s} = 41.67 kW (3)[/tex]
- Replacing (3) in (1), and solving for A, we get:
- A = 41.67 m² , which is the area of a solar collector that could collect 150MJ of energy in 1 hour, as needed.
