Answer:
The uncertainty attributable to time-of-flight and range measurements have been estimated.
Range measurement is more precise than time-of-flight.
Explanation:
Find the average time
[tex]T_{average} = \frac{5.33+5.28+5.16}{3}[/tex]
= 5.26 seconds
Standard deviation for uncertainty
[tex]\sigma = \sqrt {\frac{(5.33-5.26)^2+(5.28-5.26)^2+(5.16-5.26)^2}{3}}[/tex]
= 0.07 seconds (uncertainty attributable to time of flight)
[tex]R_{average} = \frac{83.77+83.63+83.69}{3}[/tex]
= 83.69
Standard deviation or uncertainty
[tex]\sigma = \sqrt{\frac{(83.69-83.77)^2+(83.69-83.63)^2+(83.69-83.69)^2}{3}}[/tex]
= 0.06 μm
