contestada

The displacement (in meters) of a particle moving in a straight line is given by the equation of motion s = 9/t2, where t is measured in seconds. Find the velocity of the particle at times t = a, t = 1, t = 2, and t = 3.

Respuesta :

abidemiokin

Answer:

Explanation:

Given the displacement equation expressed as s= 9/t²

Velocity is the rate of change of displacement with respect to time

V = ds/dt

s = 9t^-2

ds/dt = -18t^-3

v(t) = -18t^-3

When t = a

v(a) = -18(a)^-3

v(a) = -18/a³

When t = 1

v(1) = -18(1)^-3

v(1) = -18/1³

v(1) = -18m/s

When t = 2

v(2) = -18(2)^-3

v(2) = -18/2³

v(2) = -18/8

v(2) = -9/4 m/s

When t = 3

v(3) = -18(3)^-3

v(3) = -18/3³

v(3) = -18/27

v(3) = -2/3 m/s

Otras preguntas