Respuesta :
Answer:
The terminal velocity for both skydiver are 99.58 m/s and 121.9 m/s.
The time for both skydiver are 60.25 sec and 49.22 sec
Explanation:
Given that,
First mass = 60 kg
Second mass = 90 kg
Suppose, altitude [tex]h=6.00\times10^{3}\ m[/tex]
Area =.14 m²
C= .7
Density = 1.21 kg/m³
We need to calculate the terminal velocity
Using formula of terminal velocity
[tex]v_{1}=\sqrt{\dfrac{2m_{1}g}{\rho\times C\times A}}[/tex]
For first mass,
Put the value into the formula
[tex]v_{1}=\sqrt{\dfrac{2\times60\times9.8}{1.21\times.14\times.7}}[/tex]
[tex]v_{1}=99.58\ m/s[/tex]
For second mass,
Put the value into the formula
[tex]v_{2}=\sqrt{\dfrac{2\times90\times9.8}{1.21\times.14\times.7}}[/tex]
[tex]v_{2}=121.9\ m/s[/tex]
We need to calculate the time of first skydiver
Using formula of time
[tex]t_{1}=\dfrac{h}{v_{1}}[/tex]
Put the value into the formula
[tex]t_{1}=\dfrac{6.00\times10^{3}}{99.58}[/tex]
[tex]t_{1}=60.25\ sec[/tex]
We need to calculate the time of second skydiver
Using formula of time
[tex]t_{2}=\dfrac{h}{v_{2}}[/tex]
Put the value into the formula
[tex]t_{2}=\dfrac{6.00\times10^{3}}{121.9}[/tex]
[tex]t_{2}=49.2\ sec[/tex]
Hence, The terminal velocity for both skydiver are 99.58 m/s and 121.9 m/s.
The time for both skydiver are 60.25 sec and 49.22 sec
