Answer:
Step-by-step explanation:
The distance the light traveled to the ground is the range of the plane expressed as:
R = U*√2H/g
U is he velocity
H is the max height
g is the acc. due to gravity
Let us get U first using the formula
H = u²sin²Ф/2g
1000 = u²sin²60/2(9.81)
1000*19.62 = 0.8660u²
19620 = 0.8660u²
u² = 19620/0.8660
u² = 22655.88
u = √22655.88
u = 150.52m/s
Next is to get the range
R = 150.52√2(1000)/9.81
R = 150.52 √2000/9.81
R = 150.52√203.87
R = 150.52*14.28
R = 2149.16m
Hence the distance the light traveled to the ground is 2,149.16m
