Respuesta :

Answer:

Explanation:

The formula for calculating the magnitude of the resultant vector is expressed as;

[tex]R = \sqrt{(\sum Fx)^2+(\sum Fy)^2}[/tex]

[tex]\sum Fx[/tex] is the sum of distances along the x component

[tex]\sum Fy[/tex]  is the sum of distances along the y component

[tex]\sum Fx = 45 cos 25^0\\\sum Fx = 40.78m\\\\\sum Fy = -45 sin 25^0+30\\\sum Fx = 10.98m\\[/tex]

[tex]R = \sqrt{(40.78)^2+(10.98)^2}\\R = \sqrt{1663.0084+(120.61)}\\R = \sqrt{(1783.6184}\\R = 42.23m[/tex]

Hence the magnitude of the resultant vector is 42.23m

Answer:

NO

Explanation: