lalahylton25
contestada

Use point-slope form to write the equation of the line in slope-intercept form that passes through the points (0, -5) and (-3, 4).

Slope formula: m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction

Point-slope form: y – y1 = m(x – x1)

Slope-intercept form: y = mx + b

Choose the equation of the line.
y = –3x – 13
y = –3x – 5
y = –3x + 5
y = Negative one-third x + 13

Respuesta :

lgarciarn

Answer:

y = –3x – 5

Step-by-step explanation:

The answer is C got it right!

MrRoyal

The equation of a line can be written in either point-slope form or slope intercept form.

The equation of the line is: (b) [tex]\mathbf{y = -3x-5}[/tex]

The points are given as:

[tex]\mathbf{(x_1,y_1) = (0,-5)}[/tex]

[tex]\mathbf{(x_2,y_2) = (-3,4)}[/tex]

Start by calculating the slope using:

[tex]\mathbf{m = \frac{y_2 -y_1}{x_2 - x_1}}[/tex]

So, we have:

[tex]\mathbf{m = \frac{4--5}{-3-0}}[/tex]

[tex]\mathbf{m = \frac{9}{-3}}[/tex]

[tex]\mathbf{m = -3}[/tex]

The point slope form of the equation is:

[tex]\mathbf{y - y_1 = m(x - x_1)}[/tex]

So, we have:

[tex]\mathbf{y - -5 = -3(x - 0)}[/tex]

[tex]\mathbf{y +5 = -3x}[/tex]

Subtract 5 from both sides

[tex]\mathbf{y = -3x-5}[/tex]

Hence, the equation of the line is: (b) [tex]\mathbf{y = -3x-5}[/tex]

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