Point :
Parallel lines have same slopes.
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[tex]6x + 5y = 11[/tex]
Subtract sides -6x
[tex] - 6x + 6x + 5y = - 6x + 11[/tex]
[tex]5y = - 6x + 11[/tex]
Divided sides by 5
[tex] \frac{5}{5}y = \frac{ - 6}{5}x + \frac{11}{5} \\ [/tex]
[tex]y = - \frac{6}{5}x + \frac{11}{5} \\ [/tex]
Look :
This is the slope-intercept of the given line. We know that the coefficient of x is the slope of the linear functions in slope-intercept form.
Thus the slope of the line which we want is :
[tex]slope = - \frac{6}{5} \\ [/tex]
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We have following equation to find the point-slope form of the linear functions.
[tex]y - y(given \: point) = (slope) \times (x - x(g \: p) \: ) \\ [/tex]
Now just need to put the slope and the coordinates in the above equation.
[tex]y - ( - 8) = - \frac{6}{5} \times (x - ( - 2) \: ) \\ [/tex]
[tex]y + 8 = - \frac{6}{5}(x + 2) \\ [/tex]
To find the slope-intercept form of the above equation we need to take the y alone and then simplifies the equation.
Look :
[tex]y + 8 = - \frac{6}{5}x - \frac{12}{5} \\ [/tex]
Subtract sides by -8
[tex]y + 8 - 8 = - \frac{6}{5}x - \frac{12}{5} - 8 \\ [/tex]
[tex]y = - \frac{6}{5}x - \frac{12}{5} - \frac{40}{5} \\ [/tex]
[tex]y = - \frac{6}{5}x - \frac{52}{5} \\ [/tex]
This is what we want...
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Now we must Check the equation by using the given point :
[tex]( - 8) = - \frac{6}{5}( - 2) - \frac{52}{5} \\ [/tex]
[tex] - 8 = \frac{12}{5} - \frac{52}{5} \\ [/tex]
[tex] - 8 = \frac{ - 52 + 12}{5} \\ [/tex]
[tex] - 8 = \frac{ - 40}{5} \\ [/tex]
[tex] - 8 = - 8[/tex]
So the equation is right.
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And we're done.♥️♥️♥️♥️♥️
