Respuesta :

ChillMuse

Let width be x and height be x +5.

x(x+5) = 150

x^2 +5x = 150

x^2 + 5x - 150 = 0

(x - 10)(x + 15) = 0

Width can't be negative so it is 10 cm, and height is 15 cm.

Lanuel

If the area of a rectangle is 150 [tex]cm^2[/tex], the width of the rectangle is -15 or -10 cm.

  • Let the length of the rectangle be L.
  • Let the width of the rectangle be W.

Given the following data:

Area of a rectangle = 150 [tex]cm^2[/tex]

To find the width of the rectangle:

Translating the word problem into an algebraic equation, we have;

[tex]L = W + 5[/tex] ....equation 1.

Mathematically, the area of a rectangle is given by the formula;

[tex]Area = LW[/tex]  ....equation 2.

Substituting the values into the formula, we have;

[tex]150 = (W + 5)W\\\\150 = W^2 + 5W\\\\W^2 + 5W - 150[/tex]

Solving the quadratic equation by using factorization:

[tex]W^2 + 15W - 10W - 150\\\\W(W+15)+10(W+15)\\\\(W+15)(W+10)[/tex]

Width, W = -15 or -10 cm

Find more information: brainly.com/question/897975