MQ = 2x+2
QO= 3x-10
find x
(it’s a rhombus)

Answer:
x = 12
Step-by-step explanation:
The diagonals PN and MO are perpendicular bisectors of each other, thus
QO = MQ , substitute values
3x - 10 = 2x + 2 ( subtract 2x from both sides )
x - 10 = 2 ( add 10 to both sides )
x = 12